See Wolsey on Wiktionary
{
"head_templates": [
{
"args": {},
"expansion": "Wolsey",
"name": "en-proper noun"
}
],
"lang": "English",
"lang_code": "en",
"pos": "name",
"senses": [
{
"categories": [
{
"kind": "other",
"name": "English surnames",
"parents": [],
"source": "w"
}
],
"glosses": [
"A surname.; Alternative form of Wolseley"
],
"id": "en-Wolsey-en-name-x2mzMgp3",
"links": [
[
"surname",
"surname"
],
[
"Wolseley",
"Wolseley#English"
]
]
},
{
"categories": [
{
"kind": "place",
"langcode": "en",
"name": "Places in South Dakota, USA",
"orig": "en:Places in South Dakota, USA",
"parents": [
"Places",
"Names",
"All topics",
"Proper nouns",
"Terms by semantic function",
"Fundamental",
"Nouns",
"Lemmas"
],
"source": "w"
},
{
"kind": "place",
"langcode": "en",
"name": "Places in the United States",
"orig": "en:Places in the United States",
"parents": [
"Places",
"Names",
"All topics",
"Proper nouns",
"Terms by semantic function",
"Fundamental",
"Nouns",
"Lemmas"
],
"source": "w"
},
{
"kind": "place",
"langcode": "en",
"name": "Towns in South Dakota, USA",
"orig": "en:Towns in South Dakota, USA",
"parents": [
"Towns",
"Places",
"Polities",
"Names",
"All topics",
"Proper nouns",
"Terms by semantic function",
"Fundamental",
"Nouns",
"Lemmas"
],
"source": "w"
},
{
"kind": "place",
"langcode": "en",
"name": "Towns in the United States",
"orig": "en:Towns in the United States",
"parents": [
"Towns",
"Places",
"Polities",
"Names",
"All topics",
"Proper nouns",
"Terms by semantic function",
"Fundamental",
"Nouns",
"Lemmas"
],
"source": "w"
},
{
"_dis": "15 85",
"kind": "other",
"name": "English entries with incorrect language header",
"parents": [
"Entries with incorrect language header",
"Entry maintenance"
],
"source": "w+disamb"
},
{
"_dis": "19 81",
"kind": "other",
"name": "Pages with 1 entry",
"parents": [],
"source": "w+disamb"
},
{
"_dis": "13 87",
"kind": "other",
"name": "Pages with entries",
"parents": [],
"source": "w+disamb"
}
],
"glosses": [
"A town in South Dakota, United States."
],
"id": "en-Wolsey-en-name-fCWymetm",
"links": [
[
"South Dakota",
"South Dakota#English"
],
[
"United States",
"United States#English"
]
]
}
],
"wikipedia": [
"en:Wolsey (disambiguation)"
],
"word": "Wolsey"
}
{
"categories": [
"English entries with incorrect language header",
"English lemmas",
"English proper nouns",
"English uncountable nouns",
"Pages with 1 entry",
"Pages with entries"
],
"head_templates": [
{
"args": {},
"expansion": "Wolsey",
"name": "en-proper noun"
}
],
"lang": "English",
"lang_code": "en",
"pos": "name",
"senses": [
{
"categories": [
"English surnames"
],
"glosses": [
"A surname.; Alternative form of Wolseley"
],
"links": [
[
"surname",
"surname"
],
[
"Wolseley",
"Wolseley#English"
]
]
},
{
"categories": [
"en:Places in South Dakota, USA",
"en:Places in the United States",
"en:Towns in South Dakota, USA",
"en:Towns in the United States"
],
"glosses": [
"A town in South Dakota, United States."
],
"links": [
[
"South Dakota",
"South Dakota#English"
],
[
"United States",
"United States#English"
]
]
}
],
"wikipedia": [
"en:Wolsey (disambiguation)"
],
"word": "Wolsey"
}
Download raw JSONL data for Wolsey meaning in All languages combined (0.8kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-11-06 from the enwiktionary dump dated 2024-10-02 using wiktextract (fbeafe8 and 7f03c9b). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.